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Assuming the game ends in the first overtime, the team with the first possession wins under the following scenarios:

- scores a touchdown on the first drive
- kicks a field goal on the first drive; other team fails to score on the second drive
- both teams kick a field goal on the first and second drives; win in sudden death
- doesn't score on the first drive; defensive score during second drive
- neither team scores on first or second drives; win in sudden death

Under this overtime procedure, roughly how often should be expect the team winning the coin flip to win the game?

For an average team the empirical probabilities of the above events per drive are:

- \(\mathrm{defensiveTD} = \mathrm{Pr}(\text{defensive touchdown}) = 0.02\)
- \(\mathrm{safety} = \mathrm{Pr}(\text{safety}) = 0.001\)
- \(\mathrm{fieldGoal} = \mathrm{Pr}(\text{field goal}) = 0.118\)
- \(\mathrm{offensiveTD} = \mathrm{Pr}(\text{offensive touchdown}) = 0.200\)

We'll also use the following:

- \(\mathrm{defensiveScore} = \mathrm{Pr}(\text{any defensive score}) = \mathrm{defensiveTD} + \mathrm{safety}\)
- \(\mathrm{offensiveScore} = \mathrm{Pr}(\text{any offensive score}) = \mathrm{fieldGoal} + \mathrm{offensiveTD}\)
- \(\mathrm{noOFscore} = \mathrm{Pr}(\text{no offensive score}) = 1 - \mathrm{offensiveScore}\)
- \(\mathrm{noScore} = \mathrm{Pr}(\text{no score}) = 1 - \mathrm{offensiveScore} - \mathrm{defensiveScore}\)
- \(\mathrm{sdWin} = \mathrm{Pr}(\text{driving team winning under sudden death rules})\)

Then the probabilities of the above numbered outcomes is approximately:

- \(\mathrm{offensiveTD}\)
- \(\mathrm{fieldGoal}\times \mathrm{noOFscore}\)
- \(\mathrm{fieldGoal}\times \mathrm{fieldGoal}\times \mathrm{sdWin}\)
- \(\mathrm{noScore}\times \mathrm{defensiveScore}\)
- \(\mathrm{noScore}\times \mathrm{noScore}\times \mathrm{sdWin}\)

The last thing we need to work out is \(\text{sdWin}\). There are three ways for the team with possession to win:

- any offensive score on the first drive
- no offensive score; any defensive score on the second drive
- neither team scores on the first or second possessions; we're back to our original state

These three scenarios have values:

- \(\mathrm{offensiveScore}\)
- \(\mathrm{noOFscore}\times \mathrm{defensiveScore}\)
- \(\mathrm{noScore}\times \mathrm{noScore}\times \mathrm{sdWin}\)

Doing the math, we get that \begin{align*}

\mathrm{sdWin} &= \mathrm{offensiveScore} + \mathrm{noOFscore}\times \mathrm{defensiveScore} + {\mathrm{noScore}}^2\times\mathrm{sdWin};\\

\mathrm{sdWin} &=\frac{(\mathrm{offensiveScore} + \mathrm{noOFscore}\times \mathrm{defensiveScore})}{(1-{\mathrm{noScore}}^2)}.

\end{align*}

Putting it all together we get \[

\text{win} = \mathrm{offensiveTD} + \mathrm{fieldGoal}\times \mathrm{noOFscore} + \mathrm{noScore}\times \mathrm{defensiveScore}\\

+ (\mathrm{fieldGoal}^2+ \mathrm{noScore}^2)\times \mathrm{sdWin}.\]

Plugging in our empirical values, we finally arrive at \[\mathrm{Pr}(\text{win coin flip, win game}) = 0.560.\] For comparison, under the original sudden death rules, \[\mathrm{Pr}(\text{win coin flip, win game}) = 0.589.\] So the NFL overtime rules are still ridiculously unfair in favor of the winner of the coin flip, but not as ridiculously unfair as they were under the original sudden death rules.

How do these numerical results compare to actual outcomes? Under the current overtime rules, there have been 51 overtime games. In 27 of these the team winning the coin toss won the game, in 21 the team losing the coin toss won the game and there have been 3 ties. That puts \(\mathrm{win} = \frac{27}{48} = 0.5625\) for games not ending in ties. Close enough!

If you'd like to tweak the probabilities for each event to see how the resulting probability for the winner of the coin flip changes, I have a simple Python script here.

\mathrm{sdWin} &= \mathrm{offensiveScore} + \mathrm{noOFscore}\times \mathrm{defensiveScore} + {\mathrm{noScore}}^2\times\mathrm{sdWin};\\

\mathrm{sdWin} &=\frac{(\mathrm{offensiveScore} + \mathrm{noOFscore}\times \mathrm{defensiveScore})}{(1-{\mathrm{noScore}}^2)}.

\end{align*}

Putting it all together we get \[

\text{win} = \mathrm{offensiveTD} + \mathrm{fieldGoal}\times \mathrm{noOFscore} + \mathrm{noScore}\times \mathrm{defensiveScore}\\

+ (\mathrm{fieldGoal}^2+ \mathrm{noScore}^2)\times \mathrm{sdWin}.\]

Plugging in our empirical values, we finally arrive at \[\mathrm{Pr}(\text{win coin flip, win game}) = 0.560.\] For comparison, under the original sudden death rules, \[\mathrm{Pr}(\text{win coin flip, win game}) = 0.589.\] So the NFL overtime rules are still ridiculously unfair in favor of the winner of the coin flip, but not as ridiculously unfair as they were under the original sudden death rules.

How do these numerical results compare to actual outcomes? Under the current overtime rules, there have been 51 overtime games. In 27 of these the team winning the coin toss won the game, in 21 the team losing the coin toss won the game and there have been 3 ties. That puts \(\mathrm{win} = \frac{27}{48} = 0.5625\) for games not ending in ties. Close enough!

If you'd like to tweak the probabilities for each event to see how the resulting probability for the winner of the coin flip changes, I have a simple Python script here.

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